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I suspected...

And is there a finite orthogonal basis for the z-transform (of a finite length signal), even?

If I remember correctly, the motivation for the z-transform is that more functions have the transform defined for the z-transform than for the DT Fourier transform. And you less often need generalized functions (Dirac deltas, and their derivatives). But there is no place in which z-transforms show up in signal processing computations, I thought. Since then signals are finite-time and there isn't a need for the convergence benefits of the z-transform.



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